Genetics Question: genes and ratios ?



If I have a generation of maize cob with a phenotypic ratio of 1:1:1:1 then what would the genotype of the parents be when one of each trait is displayed:

Phenotypes:

Black grains: B
yellow grains: b
smooth grains: S
wrinkled grains: s

observed:

BS = 48
Bs = 45
bS = 44
bs = 43

So parent A & B are…?

I got BbSs for both is this right?



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2 comments a "Genetics Question: genes and ratios ?"

No, that isn’t correct. If the parents are both hybrids (BbSs), then a cross between two hybrids (a dihybrid cross) would yield a phenotypic ratio of 9:3:3:1 in the offspring (assuming typical dominant and recessive genes). In order to get the phenotypic ratio of 1:1:1:1 in the offspring, then either of two possibilities must occur: 1) one parent must be a homozygous recessive at each locus and the other parent must be heterozygous at each locus, OR 2) one parent is heterozygous at one locus, homozygous recessive at the other locus and the other parent is homzygous at the first locus and heterozygous at the other locus (kind of a mirror image of the other parent):

Possibility 1)
BbSs x bbss

So the possible offspring would be:
BbSs
Bbss
bbSs
bbss

Possibility 2)

Parents:
Bbss x bbSs

offspring:
BbSs
Bbss
bbSs
bbss

Sorry … if both parents are BbSs you’d have a ratio of 9:3:3:1. To get a ratio of 1:1:1:1, one parent is BbSs and the other is bbss.

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